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11.
Unlike call, jump does not push the next statement onto a stack. As a result, there's no way to return to where you've jumped from. ::
В отличии от вызова, переход не добавляет следующий оператор в стек. В результате, нет никакого способа вернуться туда, откуда переходили.
Translated and reviewed by акаса
Located in ../../source/label.rst:43
11 of 47 results

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